After learning the ideal gas law and the relationships it relies on to work under the certain circumstances. In this lab we conducted an experiment with a fire syringe igniter and a piece of cotton. This lab was to show the adiabatic process were the total energy(Q) equals zero, by showing a closed of syringe with certain temperature. When doing the experiment the things that changed were the pressure and volume by pushing down on the syringe causing internal heat energy which as a result caused a spark. The temperature increased the closed amount of air in the syringe is pushed down with pressure and the amount of volume is changed.
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| This is the equipment used to conduct the experiment by pushing down on the syringe with a closed amount of air causing a spark of fire in the inner tube. We conducted the experiment in order to find the final temperature in the cylinder by using the other known variables. |
The uncertainties in this experiment would be the measurements of the length of the initial and final temperature because since it was an estimation on how long the tube is when stretched out to begin the experiment although it was easier and more accurate than the final. It is because at its final length in the syringe it has to be pushed down as much as it can which as a result it was difficult to be accurate measuring the small amount of space using the equipment and using an estimation by an eye. The other estimation we had to eyeball was the inner radius of the cylinder in order to have a least amount of error and uncertainty in our final calculation to determine the final temperature of the cylinder.
This is a video of the conduction of the experiment using the fire syringe in order to find the final temperature of the cylinder. This shows that the only things that changes is the amount of pressure being pressed down fast and the amount of volume that has changed when pushed down and the temperature. We were surprised to have received a big number according to our calculations however it made sense when it came to the real value which in Fahrenheit, 451 degrees, is the temperature where paper burns. The value we had due to the uncertainties from above we were able to determine we were around the ballpark when it came to our calculations to find the final temperature which were 2590.6 Kelvins = 4203 degrees Fahrenheit. In the time of 0:33 in the video you are able to see the spark of fire when the plunger is being pushed down showing an adiabatic process when the system is insulated and the work comes from U which in this case the changes.
This is the group's calculations and measured known values in order to find the final temperature of the cylinder which was in our case 2590.6 Kelvins. The way we were able to solve this experiment numbers was using the relationship for an adiabatic process concerning the temperature and volume. The adiabatic process is when the energy Q is zero and there is only work done by the system.
This shows the activity done on Active Physics to show the characteristics of each of the processes. In this case is a picture of an isobaric process were the pressure is constant while the other variables change. As you run the activity, you see a pressure being applied showing the relationship between volume and temperature to be linear going down when ran. Q=nCpT and W=SnRdT
This demo reveals an isochoric process in which the volume is constant and the changes were applied to pressure and volume. In the demo it reveals the relationship between pressure and temperature are linear increasing in the red line. The Q=nCvT and the work applied is zero.
This demo shows the isothermal process in which the temperature remains constant and shows that the graph is a curved decreasing line. A pressure is being applied to a volume were in the end which is like the ideal gas law. In this process the Q and the work apply the same equation to express the values which is nRTln(V2/V1).
This the group's calculations and answers to the questions from 1 through 6 that show the appropriate graphs to each of the processes. And question 3 is a problem in which an isobaric process is involved using the ideal gas law to find the answer. As well as the other questions were 5 is a constant volume problem and the last which is shown in the pic below is constant temperature. 4. Answer: 25.1 dm^3; 5. 126 kPa
As explained in the caption above this is question 6, the group applied the constant temperature process were they gave a pressure and two volumes using the isothermal process to find the final pressure of the system. The answer we received from the problem is 248 kPa.
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